F(x)=-3,3x^2+10x

Solution for F(x)=-3,3x^2+10x equation:

(F)=-3.3F^2+10F

We move all terms to the left:

(F)-(-3.3F^2+10F)=0

We get rid of parentheses

3.3F^2-10F+F=0

We add all the numbers together, and all the variables

3.3F^2-9F=0

a = 3.3; b = -9; c = 0;
Δ = b2-4ac
Δ = -92-4·3.3·0
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81}=9$
$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-9}{2*3.3}=\frac{0}{6.6}
=0
$
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+9}{2*3.3}=\frac{18}{6.6}
=2+1.7142857142857/2.3571428571429
$